c++ - class template, allocator_traits -

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using namespace std::rel_ops;  template <typename t, typename = std::allocator<t> > class my_vector {     public:         typedef                                        allocator_type;         typedef typename allocator_type::value_type      value_type;          typedef typename allocator_type::size_type       size_type;         typedef typename allocator_type::difference_type difference_type;          typedef typename allocator_type::pointer         pointer;         typedef typename allocator_type::const_pointer   const_pointer;          typedef typename allocator_type::reference       reference;         typedef typename allocator_type::const_reference const_reference;          typedef typename allocator_type::pointer         iterator;         typedef typename allocator_type::const_pointer   const_iterator;      public:         friend bool operator == (const my_vector& lhs, const my_vector& rhs) {             return (lhs.size() == rhs.size()) && std::equal(lhs.begin(), lhs.end(), rhs.begin());}          friend bool operator < (const my_vector& lhs, const my_vector& rhs) {             return std::lexicographical_compare(lhs.begin(), lhs.end(), rhs.begin(), rhs.end());}          friend void swap (my_vector& x, my_vector& y) {             x.swap(y);}      private:         allocator_type _a;          pointer _b;         pointer _e; // size         pointer _l; // capacity      private:         bool valid () const {             return (!_b && !_e && !_l) || ((_b <= _e) && (_e <= _l));}          my_vector (const my_vector& that, size_type c) :                 _a (that._a) {             assert(c >= that.size());             _b = _a.allocate(c);             _e = _b + that.size();             _l = _b + c;             my_uninitialized_copy(_a, that.begin(), that.end(), begin());             assert(valid());}

i going on snippet of code, , there many things don't understand, since new c++.

  1. in "bool valid () const ", line, "(!_b && !_e && !_l)" trying do?

it's negating pointers, , don't know does, , what's it's trying accomplish.

  1. in line, "my_vector (const my_vector& that, size_type c) :," type of 'that'? reference own class?

  2. in "my_vector (const my_vector& that, size_type c) :", line doing, "_a (that._a) :" ? '_a' allocator object? because below line, there "_a.allocate(c), " , 'allocate' member function of allocator.

  3. what's purpose of having both const_pointer , pointer? also, both reference , const_reference, , both iterator , const_iterator? in first public under class my_vector?

1. statement !_x

... (where x can b, e or l.) true if pointer _x 0, null or nullptr.

it negates value of result of cast pointer boolean. therefore, (!_b && !_e && !_l) true if none of pointers set.

2) const my_vector& that ...

... const referent my_vector (which current class, constructor copies object additional information handed in via c.

3) object _a ...

... declared allocator_type _a;, allocator_type typedef a template argument defaulted std::allocator<t>.

have look:

template <typename t, typename = std::allocator<t>> ... typedef allocator_type; ... allocator_type _a; ...

the expression in question (comment) member intialization list (with 1 element)

 my_vector (const my_vector& that, size_type c) : _a (that._a)   {  // ...  }

it means "initialize _a value of that._a" in case, since both have same type, copy constructor of _a invoked.

the purpose of such typedefs enable gneric programming.

template<class container> void insert_sorted (container & object,    typename container::const_reference value) {   typename container::size_type const n = object.size(),      find_index = find_sorted(object, value);     if (find_index < n)        object.insert(object.begin()+find_index, value);     else object.push_back(value); }

the code valid if container used defines

  • a type(def) const_reference
  • a type(def) size_type
  • a method insert() takes iterator , const_reference
  • a method push_back() takes const_reference

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