Listing files in a directory recursively - python -


this question has answer here:

i want display file , folder structure recursively in output .

actual structure:

root--|       |       dira--|             |             dirc--file5             file3             file4       file1       file2       dirb--|             |             no file 

expected output:

root: file1 file2  root/dira file3 file4  root/dira/dirc file5   root/dirb no file found 

i have written following code below. need inputs in how modify required output.

code

import os.path  path = 'c:\\my\\path\\here'  root, dirnames, filenames in os.walk(path):     subdirname in dirnames:         print  subdirname      filename in filenames:         print os.path.join(root, filename) 

actual output

dira dirb c:\my\path\here\file1 c:\my\path\here\file2 dirc c:\my\path\here\dira\file3 c:\my\path\here\dira\file4 c:\my\path\here\dira\dirc\file5 

import os  path = 'root' root, dirnames, filenames in os.walk(path):     print root     filename in filenames:         print filename     if not filenames:         print 'no file found'     print 

Comments

Popular posts from this blog

javascript - DIV "hiding" when changing dropdown value -

Does Firefox offer AppleScript support to get URL of windows? -

android - How to install packaged app on Firefox for mobile? -