r - Correct number of decimal places reading in a .csv -

-

i have .csv 1 of columns contains numbers have 7 decimal places, e.g.: -117.2403266.

when i'm reading .csv r ever shows 4 decimal places column, e.g.: -117.2403. or maybe there when print shows 4 decimal places?

i thought might solved within arguments of read.csv() function, doesn't decimal places.

read.csv not truncating or rounding, print.data.frame function displaying values precision specified in options(). try:

 print(dfrm, digits=10)  > dfrm<- data.frame(test=-117.2403266) > print(dfrm)        test 1 -117.2403 > print(dfrm, digits=10)           test 1 -117.2403266

using format suggested show precision has not been lost, return character vector, might not suitable assignment when numeric value expected.

edit of 2 yr-old post: topic might bring question regarding how integers can imported when larger .machine$integer.max #[1] 2147483647, since such can internally stored 'numeric'-abscissa values, maximum 2^52 (or 2^53-1, forget is). when these read in scan-based function (as 0f read.*-family), need declare 'numeric' rather 'integer':

> str( scan(text="21474836470", what=integer())) error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,  :    scan() expected 'an integer', got '21474836470' > str( scan(text="21474836470", what=numeric())) read 1 item  num 2.15e+10 > str( read.table(text="21474836470", colclasses="integer")) error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,  :    scan() expected 'an integer', got '21474836470' > str( read.table(text="21474836470", colclasses="numeric")) 'data.frame':   1 obs. of  1 variable:  $ v1: num 2.15e+10

if don't specify type or mode "what", scan assume numeric() , succeed.


Comments

Post a Comment

Popular posts from this blog

javascript - DIV "hiding" when changing dropdown value -

-
this related previous question asked: hide / show multiple divs i have code in place previous question , seems work ok apart when change value in dropdown "after" ticket selection made. i have number of javascrpts in place wondering if there clash somewhere? first bit of code in head of document. <head> <script type="text/javascript"> $(function() { $('.cat_dropdown').change(function() { $('#paymethod').toggle($(this).val() >= 2); }); }); </script> <script type="text/javascript"> $(document).ready(function () { $(".paymentmethod").click(function () { $(".paymentinfo").hide(); switch ($(this).val()) { case "credit card authorisation": $("#pay0").show("slow"); break; ...
Read more

html - Accumulated Depreciation of Assets on php -

-
i have problem table print out asset accumulated depreciation on php, stright line method. $query = mysqli_query($connect, "select current_value, salvage_value, useful_life, placed_service assets"); if(!$query){ echo 'could not run query b: ' . mysqli_error($connect); exit; } while($asset = mysqli_fetch_row($query)){ echo "assets :"; print_r($asset); $month = 12; $year = date('y',strtotime($asset[3])); $first_year = $month - ((int)date('m',strtotime($asset[3]))-1); $last_year = $month - $first_year; $first = round((($asset[0] - $asset[1])/$asset[2])*(($first_year)/12),0); $last = round((($asset[0] - $asset[1])/$asset[2])*(($last_year)/12),0); $others = ($asset[0] - $asset[1])/$asset[2]; echo "<table border=1>"; echo "<tr><th>year</th><th>book value year start</th><th>depreciation expense</th><th...
Read more

#1062 - Duplicate entry '' for key 'unique_id' When Trying to add UNIQUE KEY (MySQL) -

-
Image
i've got error on mysql while trying add unique key. here's i'm trying do. i've got column called 'unique_id' varchar(100). there no indexes defined on table. i'm getting error: #1062 - duplicate entry '' key 'unique_id' when try add unique key. here screenshot of how i'm setting in phpmyadmin: here mysql query that's generate phpmyadmin: alter table `wind_archive` add `unique_id` varchar( 100 ) not null first , add unique ( `unique_id` ) i've had problem in past , never resolved rebuilt table scratch. unfortunately in case cannot there many entries in table already. help! the error says all: duplicate entry '' so run following query: select unique_id,count(unique_id) yourtblname group unique_id having count(unique_id) >1 this query show problem select * yourtblname unique_id='' this show there values have duplicates. trying create unique index on field duplicates. need r...
Read more