coding style - Scala - Pattern matching result of a for comprehension -

i'm performing pattern match on result of for-comprehension follows

val validxsrf = for(     cookie <- request.cookies.get("xsrf-token");      header <- request.headers.get("x-xsrf-token");      if cookie.value == header ) yield true;  validxsrf match {    case some(true) => callbackfunc();    case none       => throw new xsrfexception(); } 

however feels little overly verbose - there cleaner way of expression this?

ideally i'd love like

for(....) match { .... } 

however not appear possible in scala without wrapping entire for-comprehension in brackets.

is there cleaner / more elegant way of expressing logic?

you abbreviate things bit (assuming callbackfunc returns string):

def validxsrf():string = {   val xsrf = for{     cookie <- request.cookies.get("xsrf-token")     header <- request.headers.get("x-xsrf-token")      if cookie.value == header   } yield callbackfunc()    xsrf.getorelse(throw new xsrfexception()) } 

now if didn't want throw exception on failure case, redefine validxsrf method around returning try instead, this:

def validxsrf():try[string] = {   val xsrf = for{     cookie <- request.cookies.get("xsrf-token")     header <- request.headers.get("x-xsrf-token")      if cookie.value == header   } yield callbackfunc()    xsrf.fold[try[string]](failure(new xsrfexception()))(success(_)) }